Amir Khan announces December fight with Lamont Peterson
Last updated on .From the section Boxing
Amir Khan will defend his WBA and IBF light-welterweight titles against American Lamont Peterson in Washington DC on 10 December.
Mandatory IBF challenger Peterson, 27, has won all but two of his 31 fights. His only defeat was against Timothy Bradley in California two years ago.
Khan said: "I know Lamont is a strong contender but it doesn't matter that I'm fighting him in his back yard.
"I'm coming in as champion and I will leave as champion."
Khan defended the belts in Las Vegas against American Zab Judah in July. The British fighter's next challenge will be the third time he has fought in America.
It is expected to be the last time that Khan fights at 140lbs as he is looking to step up to welterweight to set up a fight against unbeaten Floyd Mayweather next summer.
Khan, who has lost one of his 27 fights, said: "I always said I wanted to be active and a true world champion and I will prove it on 10 December."
Peterson, who was born in Washington DC, added: "I respect Khan for his accomplishments and as a champion, but this is something that goes beyond all that.
"This is the moment I've been waiting for my entire career, and to win a world title at home is something that I will remember forever.
"On 10 December, I will make my dreams come true and ruin Amir's plans to reign over his division."
Richard Schaefer, chief executive of promoters Golden Boy, confirmed the fight will take place at the Washington DC Convention Center.
