Wuxi Classic: Neil Robertson will face Joe Perry in China final

Australian snooker player Neil Robertson
Neil Robertson is through to the Wuxi Classic final, which would be his 10th ranking title

Defending champion Neil Robertson says nothing less than a win will do when he plays Joe Perry in the final of the Wuxi Classicexternal-link in China on Sunday.

Australia's Robertson, who reached the last four with three Englishmen, beat Barry Hawkins 6-3 in his semi-final, while Perry overcame Martin Gould 6-4.

World number three Robertson, 32, is aiming to win the £85,000 top prize for the second successive year.

He said: "I'm very determined and nothing less than a win is acceptable."

A victory in Sunday's final would give Robertson a 10th ranking title of his career, which would put him level with Jimmy White at seventh on the all-time winners' list.

He beat Scotland's John Higgins in the 2013 final.

Perry, ranked 15th in the world, has only one tournament victory at a ranking event, beating Mark Selby at the 2013 Yixing Open.

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